Respuesta :

Answer:

In a series circuit, adding another resistor affects the total current flowing through the circuit.

Explanation:

When another resistor is connected in series in a circuit, the total resistance of the circuit increases. As a result, the total current flowing through the circuit decreases, according to Ohm's Law. This decrease in current occurs because the voltage remains constant while the resistance increases, leading to a reduction in current.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Ohm's Law:}}\\\\\Delta V=IR\\\\\text{Where:}\\\bullet \ \Delta V \ \text{represents the} \ \bold{voltage}\\\bullet \ I \ \text{represents the } \bold{current}\\\bullet \ R \ \text{represents the} \ \bold{resistance}\end{array}\right}[/tex]

Adding another resistor in series increases the total resistance, which decreases the total current in the circuit according to Ohm's Law. The current is inversely proportional to the total resistance.

In a series circuit, when another resistor is connected in series, the total resistance of the circuit increases. This is because the total resistance in a series circuit is the sum of the individual resistances:

R(total) = R1 + R2 + ... + Rn

According to Ohm's Law (V = IR), if the voltage (V) supplied by the battery remains constant and the resistance (R) increases, the total current (I) in the circuit will decrease. This is because the current is inversely proportional to the resistance:

I = V / R(total)

For example, if you have a circuit with an initial resistor of 2 ohms and add another resistor of 3 ohms in series, the total resistance becomes:

R(total) = 2 ohms + 3 ohms = 5 ohms

If the voltage supplied by the battery is 10 volts, initially the current is:

I = V / R = 10V / 2 ohms = 5A

After adding the second resistor, the new current becomes:

I = V / R = 10V / 5 ohms = 2A

Therefore, by adding more resistors in series, the total current in the circuit decreases.

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