Question

A baseball is hit with a vertical speed of 10m/s and a horizontal speed of 30m/s.how long will the ball remain in the air

Answer 1

First find the direction velocity
Vo = $\sqrt{Vx^2 + Vy^2} = \sqrt{30^2 + 10^2} = \sqrt{1000}$
tan θ = vy/vx = 10/30 = 1/3
so, sin θ = 1/√10 = √10/10

and time to reach further point is same with how long the ball in the air

$t = \frac{2vo . sin \alpha }{g} = \frac{2. \sqrt{1000} . 1/ \sqrt{10} }{10}$
$= \frac{2 . \sqrt{100} }{10} = \frac{2 . 10}{10} = 2 second$

Sorry for bad english (from Indonesian)