Question

A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet.
Compared to the acceleration due to gravity near Earth’s surface, the acceleration due to gravity near the
surface of the planet is approximately
(1) the same (3) one-half as great
(2) twice as great (4) four times as great

Answer 1

(3) one-half as great;
Consider the relationship:
$y_{f}-y_{i}=v_{i}t+ \frac{1}{2} at^{2}$
with your data you get:
$-22=0+ \frac{1}{2}a*9$
$a=-4.88m/s^{2}$
approx one-half of $g=-9.8m/s^{2}$