Respuesta :
3b+8≥14
Subtract 8 from both sides
3b≥14-8
3b≥6
Divide both sides by 3
b≥6/3
b≥2
Subtract 8 from both sides
3b≥14-8
3b≥6
Divide both sides by 3
b≥6/3
b≥2
Answer:
The solution of the given inequality [tex]3b+8\geq 14[/tex] is: [tex][2, \infty)[/tex]
Step-by-step explanation:
Given the inequality equation: [tex]3b+8\geq 14[/tex]
Subtraction property of equality states that you subtract the same number to both sides of an equation.
Subtract 8 to both sides of an equation.
[tex]3b+8-8\geq 14-8[/tex]
Simplify:
[tex]3b\geq 6[/tex]
Division property of equality states that you divide the same number to both sides of an equation.
Divide both sides by 3 we get;
[tex]\frac{3b}{3} \geq \frac{6}{3}[/tex]
Simplify:
[tex]b\geq 2[/tex]
therefore, the solution of the given inequality is: [tex]b\geq 2[/tex] or [tex][2, \infty)[/tex]