I'd be happy to help!
To find the slope of the line segment JK that passes through points J(6,1) and K(-3,8), you can use the formula for slope:
Slope (m) = (y2 - y1) / (x2 - x1)
1. Assign coordinates: Let J(6,1) be (x1, y1) and K(-3,8) be (x2, y2).
2. Substitute the coordinates into the formula:
m = (8 - 1) / (-3 - 6)
m = 7 / -9
3. Simplify the fraction:
m = -7/9
Therefore, the slope of the line JK is -7/9.
The correct answer is not provided in the options, so the correct answer would be: The slope of JK is -7/9.
