Answer:
To express the given expression \((x-2)(3x+1)\) as a trinomial, we can first distribute each term in the first binomial to each term in the second binomial:
\[
(x-2)(3x+1) = x \cdot (3x+1) - 2 \cdot (3x+1)
\]
Expanding further:
\[
= 3x^2 + x - 6x - 2
\]
Combining like terms:
\[
= 3x^2 - 5x - 2
\]
So, the trinomial form of \((x-2)(3x+1)\) is \(3x^2 - 5x - 2\).
