Question

plss someone help answer thiss

Which set of side lengths could be the side lengths in a
right triangle?
A) 8, 20, 25
B) 9, 40, 41
C) 10, 40, 45
D) 6, 30, 31

Answer 1

the sets that could be the side lengths in a right triangle are A)
8
,
20
,
25
8,20,25, B)
9
,
40
,
41
9,40,41, and D)
6
,
30
,
31
6,30,31.

Answer 2

Answer:

The Answer is B) 9,40,41

Step-by-step explanation:

To solve this, all you need to do is apply Pythagoras theorem which
$c^{2} =a^{2} +b^{2}$ hence
$c=\sqrt{a^{2}+b^{2} }$ if we apply a little algebra and square root both sides.
c represents the hypotenuse which is the longest side.
a and b represent the other 2 smaller sides.

This is multiple choice all we need to do is ensure that when we square the 2 smaller sides, add them together and square root it, we get the third number.

Starting with A)
$\sqrt{8^{2}+20^{2} }$ is equal to 21.5.
21.5 is not equal to 25
hence 8,29 and 25 are not lengths of a right angled triangle.

B)
$\sqrt{9^{2} +41^{2} }$ is equal to 41

41 is equal to 41

hence 9,40 and 41 are lengths of a right angled triangle.

C)

$\sqrt{10^{2} +40^{2} }$ is equal to 41.2

41.2 is not equal to 45

hence 10,40 and 45 are not lengths of a right angled triangle.

D)

$\sqrt{6^{2} +30^{2} }$ is equal to 30.6

30.6 is not equal to 31
hence 6,30 and 41 are not lengths of a right angled triangle.

Hopefully this helped :)