Respuesta :
Answer:
To find the molarity of the acid (HBr), we can use the equation:
�
acid
×
�
acid
=
�
base
×
�
base
M
acid
×V
acid
=M
base
×V
base
Where:
�
acid
M
acid
= molarity of the acid (HBr)
�
acid
V
acid
= volume of the acid used (in liters)
�
base
M
base
= molarity of the base (CsOH)
�
base
V
base
= volume of the base used (in liters)
Given:
�
base
=
0.20
M
M
base
=0.20M
�
base
=
12.45
mL
−
4.05
mL
=
8.4
mL
=
0.0084
L
V
base
=12.45mL−4.05mL=8.4mL=0.0084L
�
acid
=
6.5
mL
=
0.0065
L
V
acid
=6.5mL=0.0065L
Substituting these values into the equation:
�
acid
×
0.0065
L
=
0.20
M
×
0.0084
L
M
acid
×0.0065L=0.20M×0.0084L
Now, solve for
�
acid
M
acid
:
�
acid
=
0.20
M
×
0.0084
L
0.0065
L
M
acid
=
0.0065L
0.20M×0.0084L
�
acid
=
0.00168
0.0065
M
acid
=
0.0065
0.00168
�
acid
≈
0.258
M
M
acid
≈0.258M
So, the molarity of the acid (HBr) is approximately
0.258
M
0.258M.
Explanation:
