Question

PLEASE HELP! will give brainliest
According to Ohm's Law, the electric current "I", in amperes, in a circuit varies directly as the
voltage "V" When 12 volts are applied, the current is 3 amperes. What is the current when 48 volts
are applied?

Answer 1

According to Ohm's Law, the relationship between electric current (I), voltage (V), and resistance (R) in a circuit is given by the formula:

                                                      $I= \frac{V}{R}$

In this case, we're assuming that the resistance remains constant. Since the problem states that the current varies directly with the voltage, we can set up a proportion to solve for the current:

                                                  $\frac{I_{1} }{V_{1} } = \frac{I_{2} }{V_{2} }$

Where:

• $I_{1}$ = 3 amperes (current when 12 volts are applied)
• $V_{1}$ = 12 volts
• $I_{2}$ is the current we want to find
• $V_{2}$ =48 volts

Now, let's plug in the values and solve for $I_{2}$ :

                                                    $\frac{3}{12} =\frac{I_{2} }{48}$

To solve for $I_{2}$, we multiply both sides by 48:

                                                $I_{2} = \frac{3(48)}{12} \\I_{2} = \frac{144}{12} \\\\I_{2} = 12$

So, when 48 volts are applied, the current in the circuit is 12 amperes.