Answer:
668,000 joules of energy
Explanation:
To melt 2kg of ice at 0 degrees Celsius, you'll need to provide the latent heat of fusion for ice. Here's how to calculate the energy required:
1. **Latent heat of fusion:** The latent heat of fusion of ice is the energy required to change 1 gram of ice at 0°C to 1 gram of water at 0°C without a change in temperature. The typical value for the latent heat of fusion of ice is 334 kilojoules per kilogram (kJ/kg) or 3.34 x 10^5 joules per kilogram (J/kg).
2. **Energy needed:** We know the mass of ice to melt (m) is 2kg and the latent heat of fusion (L_f) is 3.34 x 10^5 J/kg. We can use the following formula to find the energy (Q) required:
Q = m * L_f
3. **Calculation:** Substitute the values:
Q = 2kg * (3.34 x 10^5 J/kg)
Q = 6.68 x 10^5 Joules
Therefore, approximately 668,000 joules of energy are needed to melt 2kg of ice at 0 degrees Celsius.
