To determine how many milliliters (mL) of a 1.50 M NaCl solution contains 20.0 g of NaCl, we can follow these steps:
1. Calculate the molar mass of NaCl:
- The molar mass of NaCl is 58.44 g/mol (sodium (Na): 22.99 g/mol, chlorine (Cl): 35.45 g/mol).
2. Convert the mass of NaCl given (20.0 g) to moles:
- Number of moles = Mass (g) / Molar mass (g/mol)
- Number of moles = 20.0 g / 58.44 g/mol ≈ 0.342 moles
3. Use the definition of molarity to find the volume of the solution:
- Molarity (M) = Moles of solute / Volume of solution (L)
- We have the molarity (1.50 M) and moles of solute (0.342 moles), so we can rearrange the formula to solve for volume:
- Volume of solution (L) = Moles of solute / Molarity
- Volume of solution (L) = 0.342 moles / 1.50 mol/L ≈ 0.228 L
4. Convert the volume from liters to milliliters:
- 1 L = 1000 mL
- Volume of solution (mL) = 0.228 L * 1000 mL/L = 228 mL
Therefore, 228 milliliters of a 1.50 M NaCl solution contains 20.0 grams of NaCl.Answer:
Explanation:
