To find the molar concentration of the NaOH solution, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between NaOH and H2SO4:
NaOH + H2SO4 → Na2SO4 + H2O
From the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of H2SO4. Now, we can use the given information to find the molar concentration of the NaOH solution.
Calculate the moles of H2SO4 used in the reaction:
Moles of H2SO4 = Volume (L) × Molarity (M)
Moles of H2SO4 = 0.04249 L × 0.219 M = 0.00919 moles
Since the mole ratio between NaOH and H2SO4 is 1:1, the moles of NaOH used in the reaction are also 0.00919 moles.
Calculate the molar concentration of NaOH:
Molarity of NaOH = Moles of NaOH / Volume of NaOH solution (L)
First, we need to find the volume of the NaOH solution. We know the mass of NaOH and its molar mass:
Mass of NaOH = 25.0 g
Molar mass of NaOH = 22.99 g/mol (Na) + 15.999 g/mol (O) + 1.007 g/mol (H) = 39.996 g/mol
Now, we can find the volume of the NaOH solution:
Volume of NaOH solution = Mass of NaOH / Molar mass of NaOH
Volume of NaOH solution = 25.0 g / 39.996 g/mol = 0.00624 L (approximately)
Now, we can find the molar concentration of the NaOH solution:
Molarity of NaOH = 0.00919 moles / 0.00624 L = 1.474 M
So, the molar concentration of the NaOH solution is approximately 1.474 M.
