Answer:
Step-by-step explanation: (a) The symbolic form of the argument can be represented as follows:
P: I go to my first class tomorrow.
Q: I get up early.
R: I go to the dance tonight.
S: I stay up late.
T: I exist on only five hours of sleep.
Premises:
1. P → Q
2. R → S
3. S ∧ Q → T
4. ¬T
Conclusion:
5. ¬P ∨ ¬R
(b) To check the validity of the argument using formal proof, we will use the rules of inference and laws of logic. Here is a step-by-step proof:
1. P → Q (Premise)
2. R → S (Premise)
3. S ∧ Q → T (Premise)
4. ¬T (Premise)
5. ¬(S ∧ Q) → ¬T (Implication rule, 3)
6. (¬S ∨ ¬Q) → ¬T (De Morgan's law, 5)
7. ¬T → (¬S ∨ ¬Q) (Contrapositive, 6)
8. ¬T → (¬Q ∨ ¬S) (Commutation, 7)
9. ¬T → (Q → ¬S) (Implication rule, 8)
10. ¬T → (R → ¬S) (Transitivity, 2, 9)
11. (¬T ∨ (R → ¬S)) (Implication rule, 10)
12. (¬T ∨ (¬R ∨ ¬S)) (Implication rule, 11)
13. (¬R ∨ (¬T ∨ ¬S)) (Commutation, 12)
14. (¬R ∨ (¬S ∨ ¬T)) (Association, 13)
15. (¬S ∨ (¬R ∨ ¬T)) (Commutation, 14)
16. (S → (¬R ∨ ¬T)) (Implication rule, 15)
17. (Q → (S → (¬R ∨ ¬T))) (Implication rule, 16)
18. (Q → (R → (S → (¬R ∨ ¬T)))) (Implication rule, 17)
19. (P → (Q → (R → (S → (¬R ∨ ¬T))))) (Implication rule, 18)
20. (P → (Q → (R → (S → (¬R ∨ ¬T))))) ∧ (¬T) (Conjunction, 4, 19)
21. (P → (Q → (R → (S → (¬R ∨ ¬T))))) ∧ (¬T) → (¬P ∨ ¬R) (Implication rule)
22. ¬P ∨ ¬R (Modus Ponens, 20, 21)
Therefore, the argument is valid as we have derived the conclusion (¬P ∨ ¬R) using formal proof.