Juanita has 3 rectangular cards that are 5 inches by 9 inches. How can she arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter? How will the area of the polygon compare to the combined area of the 3 cards?

To arrange the three rectangular cards without overlapping to form a larger polygon with the smallest possible perimeter, Juanita can arrange them in a triangular shape.

She can place two rectangular cards side by side to form a larger rectangle with dimensions 5 inches by 18 inches. Then, she can place the third rectangular card on top of the larger rectangle, aligning one of its shorter sides with the longer side of the larger rectangle. This will create a triangular shape.

The perimeter of the resulting polygon will be the sum of the lengths of the sides of the triangle. In this case, the perimeter will be 5 inches + 18 inches + 9 inches = 32 inches.

The area of the larger polygon formed by arranging the three cards will be the same as the combined area of the three individual cards. The combined area of the three cards is 3 * (5 inches * 9 inches) = 135 square inches.

Juanita has 3 rectangular cards that are 5 inches by 9 inches. How can she arrange the​ cards, without​ overlapping, to make one larger polygon with the smallest possible​ perimeter? How will the area of the polygon compare to the combined area of the 3 ​cards?

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Juanita has 3 rectangular cards that are 5 inches by 9 inches. How can she arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter? How will the area of the polygon compare to the combined area of the 3 cards?