Question

What is the equation of the line in slope-intercept form that passes through point (1, –2) and is parallel to the line y = 3x – 2? Show all necessary steps

Answer 1

Answer:

$y=3x-5$

Step-by-step explanation:

In order for an equation to be parallel to another, their slope must be the same. So we know the $m$ in $y=mx+b$ is equal to $3$. Then, we can plug the point into the equation which will get us $-2=3(1)+b$. Now, we simplify:

$-2=3+b$
$-5=b$
$b=-5$

Now that we have both our $m$ and our $b$, formatting the equation in slope-intercept form will give us our answer of $y=3x-5$.

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Answer 2

Answer:

y = 3x-5

Step-by-step explanation:

y = 3x-2 is in slope intercept form with a slope of 3 and a y intercept of 2.  We know that parallel lines have the same slope, so the slope of the new line would be 3.

Writing the equation for the new line in slope intercept form:

y = mx+b where m is the slope and b is the y intercept

y = 3x+b

Substituting the given point into the line:

-2 = 3(1)+b

-2 = 3+b

-5 = b

The line is

y = 3x-5