Question

If m<1 = 7x + 6 and m<2 = 8x - 6, find the value of x so that p is perpendicular to q

Answer 1

If the lines are perpendicular, then angle 1 and angle 2 are both equal to 90 degrees.Angle 1 m<1 = 7x + 67x + 6 = 907x = 84X = 12
the same goes to angle 2Angle 2 m <2= 8x – 68x – 6 = 908x = 84X = 10.5

Answer 2

Answer:

x = 12

Step-by-step explanation:

Given: $\angle 1=7x+6$

$\angle 2=8x-6$

∠1 and ∠2 form by two intersection line p and q.

p is perpendicular to q.

Therefore, ∠1 = ∠2 = 90°

So, 7x + 6 = 90°

7x = 84

x = 12

8x - 6 = 90°

8x = 96

x = 12

7x + 6 = 8x - 6

x = 6 + 6

x = 12

So, we get x=12 from all three equations.

hence, The value of x is 12