Answer:
To calculate the energy required to heat 561.0 g of aluminum from 3.1 °C to 20.6 °C, you can use the formula:
\[ q = mcΔT \]
Where:
- \( q \) is the energy (in joules) required
- \( m \) is the mass of aluminum (561.0 g)
- \( c \) is the specific heat capacity of aluminum (0.903 J/g°C)
- \( ΔT \) is the change in temperature (20.6°C - 3.1°C = 17.5°C)
Now, substitute the values into the formula:
\[ q = (561.0 g) * (0.903 J/g°C) * (17.5°C) \]
\[ q = 9027.7875 J \]
To ensure the correct number of significant digits in the answer, the energy required to heat 561.0 g of aluminum from 3.1°C to 20.6°C is approximately 9028 J.
Explanation:
