Respuesta :
To find the surface area of each block, we need to calculate the area of each face and then sum them up.
For the first block with dimensions 5.8 m x 3 m x 6 m:
1. The area of the top and bottom faces (5.8 m x 6 m): \(5.8 \times 6 \times 2 = 34.8 \, \text{m}^2\)
2. The area of the front and back faces (3 m x 6 m): \(3 \times 6 \times 2 = 36 \, \text{m}^2\)
3. The area of the left and right faces (5.8 m x 3 m): \(5.8 \times 3 \times 2 = 34.8 \, \text{m}^2\)
Total surface area = \(34.8 + 36 + 34.8 = 105.6 \, \text{m}^2\)
For the second block with dimensions 5.2 m x 5.8 m x 5.2 m:
1. The area of the top and bottom faces (5.2 m x 5.2 m): \(5.2 \times 5.2 \times 2 = 54.08 \, \text{m}^2\)
2. The area of the front and back faces (5.8 m x 5.2 m): \(5.8 \times 5.2 \times 2 = 60.16 \, \text{m}^2\)
3. The area of the left and right faces (5.2 m x 5.8 m): \(5.2 \times 5.8 \times 2 = 60.16 \, \text{m}^2\)
Total surface area = \(54.08 + 60.16 + 60.16 = 174.4 \, \text{m}^2\)
So, the surface area of the first block is \(105.6 \, \text{m}^2\) and the surface area of the second block is \(174.4 \, \text{m}^2\).
For the first block with dimensions 5.8 m x 3 m x 6 m:
1. The area of the top and bottom faces (5.8 m x 6 m): \(5.8 \times 6 \times 2 = 34.8 \, \text{m}^2\)
2. The area of the front and back faces (3 m x 6 m): \(3 \times 6 \times 2 = 36 \, \text{m}^2\)
3. The area of the left and right faces (5.8 m x 3 m): \(5.8 \times 3 \times 2 = 34.8 \, \text{m}^2\)
Total surface area = \(34.8 + 36 + 34.8 = 105.6 \, \text{m}^2\)
For the second block with dimensions 5.2 m x 5.8 m x 5.2 m:
1. The area of the top and bottom faces (5.2 m x 5.2 m): \(5.2 \times 5.2 \times 2 = 54.08 \, \text{m}^2\)
2. The area of the front and back faces (5.8 m x 5.2 m): \(5.8 \times 5.2 \times 2 = 60.16 \, \text{m}^2\)
3. The area of the left and right faces (5.2 m x 5.8 m): \(5.2 \times 5.8 \times 2 = 60.16 \, \text{m}^2\)
Total surface area = \(54.08 + 60.16 + 60.16 = 174.4 \, \text{m}^2\)
So, the surface area of the first block is \(105.6 \, \text{m}^2\) and the surface area of the second block is \(174.4 \, \text{m}^2\).
