Answer:
3. two real solutions
Step-by-step explanation:
For this problem, we will use the formula b^2-4ac.
If the equation is negative, it will have no real solutions.
If the equation is positive it will have two real solutions.
If the equation is zero, it will have one real solution.
So, following the format of ax^2+bx+c, we can plug in the equation as (0)^2-4(1)(-44).
Now, we can simplify it.
=0-(4)(-44)
=0-(-176)
=0+176
=176
So, since the equation is positive, we have two real solutions.
Hope this helps!
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