To find out how many moles are in 12.65 grams of Al2(SO4)3, you can follow these steps:
1. Calculate the molar mass of Al2(SO4)3.
2. Use the formula: Moles = Mass / Molar mass.
Let's start by calculating the molar mass of Al2(SO4)3:
- Aluminum (Al) has a molar mass of approximately 26.98 g/mol.
- Sulfur (S) has a molar mass of approximately 32.06 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.
The molar mass of Al2(SO4)3 can be calculated as follows:
Molar mass = (2 x Molar mass of Al) + (3 x Molar mass of S) + (12 x Molar mass of O)
Molar mass = (2 x 26.98) + (3 x 32.06) + (12 x 16.00)
Molar mass = 53.96 + 96.18 + 192.00
Molar mass = 342.14 g/mol
Now, use the formula Moles = Mass / Molar mass:
Moles = 12.65 g / 342.14 g/mol
Moles = 0.03698 moles
Therefore, there are approximately 0.03698 moles of Al2(SO4)3 in 12.65 grams of the compound.
