Sure, here's the explanation using symbols instead of code:
To calculate the energy released in one fusion reaction using the equation E = mc^2, where m is the mass converted into energy, c is the speed of light, and E is the energy produced, we need to know the mass converted into energy.
Let's assume that the mass converted into energy in one fusion reaction is m = 1 gram (0.001 kilograms), which is a common approximation for nuclear reactions.
Given:
- m = 0.001 kilograms
- Speed of light (c) is approximately 3 x 10^8 meters/second
Plugging these values into the equation E = mc^2:
E = (0.001 kg) x (3 x 10^8 m/s)^2
E = 0.001 x 9 x 10^16
E = 9 x 10^13 Joules
This value is in joules (J), which is the proper unit of energy. However, none of the provided answer options matches this result exactly. The closest option is "4.3 x 10^-10 J," but this is significantly smaller than the calculated value. Therefore, none of the provided answer options is correct based on the calculation using E = mc^2 with m = 0.001 kilograms.
