Answer:
To find the equation of a line given its slope and a point it passes through, follow these steps:
1. Start with the point-slope form of a linear equation: \( y - y_1 = m(x - x_1) \), where \( (x_1, y_1) \) is the given point and \( m \) is the slope of the line.
2. Plug in the values of the given point (-10, -5) into the equation: \( y - (-5) = -1(x - (-10)) \).
3. Simplify the equation: \( y + 5 = -1(x + 10) \).
4. Expand the equation: \( y + 5 = -x - 10 \).
5. Rearrange the equation into slope-intercept form (y = mx + b): \( y = -x - 15 \).
Therefore, the equation of the line with a slope of -1 passing through the point (-10, -5) is \( y = -x - 15 \).
