Given the information provided:
- In triangle AABC, A = 50° and is an isosceles triangle,
- LM || BC, 2B = 2C.
(i) Name the type of quadrilateral LMCB:
LMCB is a parallelogram because LM is parallel to BC.
(ii) The measure of 2LMC:
Since LM || BC, 2LMC = 2C = 50° (as given).
(iii) If LALM = LABC, then LM | BC (property used):
If the alternate angles are equal, then the lines are parallel. Therefore, LM || BC is a property of alternate angles.
(iv) The measure of ZALM:
In triangle AALM, as A = 50° and it is an isosceles triangle, so AAA is 180°. Since ALM = MLA, then ZALM = (180 - 50) / 2 = 65°.
Therefore, the measure of ZALM is 65°.