If the total area of the pyramid is 1276, what is the height of a triangle??

Answer:
18 cm
Step-by-step explanation:
The total surface area of a square pyramid is given by the formula:
[tex] \Large\boxed{\boxed{\sf A = B + \dfrac{1}{2}Pl}} [/tex]
Where:
Given that the total area of the square pyramid is [tex] 1276 \, \text{cm}^2 [/tex] and the side of the square base is [tex] 22 \, \text{cm} [/tex], we can first find the perimeter of the base:
[tex] \textsf{Perimeter} = 4 \times \textsf{Side} \\\\ = 4 \times 22 \\\\= 88 \, \textsf{cm} [/tex]
Now, using the formula for the total surface area and plugging in the values:
[tex] 1276 = 22^2 + \dfrac{1}{2} \times 88 \times l [/tex]
[tex] 1276 = 484 + 44l [/tex]
[tex] 44l = 1276 - 484 [/tex]
[tex] 44l = 792 [/tex]
[tex] l = \dfrac{792}{44} [/tex]
[tex] l = 18 \, \text{cm} [/tex]
So, the slant height of the square pyramid is [tex] 18 \, \text{cm} [/tex].