Question

An object resting on a horizontal frictionless surface is connected to a fixed string. The object is displaced 14cm from its equilibrium position and released. At t = 0.65 seconds, it is 6.70 cm from its equilibrium. What is the object’s period of oscillation?

Answer 1

Answer:

3.81 s

Explanation:

The object oscillates along a cosine wave:

x = A cos (2πt / T),

where A is the amplitude and T is the period.

Given that A = 14, and x = 6.70 when t = 0.65:

6.70 = 14 cos (2π (0.65) / T)

0.479 = cos (4.08 / T)

1.07 = 4.08 / T

T = 3.81

The period is 3.81 seconds.