The cost of cheese at three stores is a function of the weight of the cheese. The cheese is not prepackaged, so a customer can buy any amount of cheese. Store A sells the cheese for dollars per pound. Store B sells the same cheese for dollars per pound and a customer has a coupon for $5 off the total purchase at that store. Store C is an online store, selling the same cheese at a dollar per pound, but with a $10 delivery fee. This graph shows the price functions for stores A, B, and C. How many pounds would a customer need to order to make Store C a good option?

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Answer:

Since the inequalities have no solution, there is no amount of cheese a customer could order to make Store C a better option in this scenario.

Step-by-step explanation:

To determine when Store C becomes a good option compared to Store A and Store B, we need to find the point where the cost at Store C is less than or equal to the costs at Store A and Store B, taking into account the delivery fee.

Here are the steps to solve this problem:

1. Define the cost functions:

- Store A: Cost = \(x\) dollars per pound

- Store B: Cost = \(x - 5\) dollars per pound (after applying the $5 coupon)

- Store C: Cost = \(x + 10\) dollars per pound (including the $10 delivery fee)

2. Set up the inequality to find when Store C becomes a better option:

\(x + 10 \leq x\) (Store C cost is less than or equal to Store A cost)

\(x + 10 \leq x - 5\) (Store C cost is less than or equal to Store B cost after coupon)

3. Solve the inequalities:

For Store C to be a better option than Store A: \(x + 10 \leq x\) becomes \(10 \leq 0\), which is not possible.

For Store C to be a better option than Store B: \(x + 10 \leq x - 5\) becomes \(10 \leq -5\), which is also not possible.

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