Respuesta :
Answer:
To solve this problem, we first need to determine the amount of cobalt(III) oxide produced when 41% of the reaction is complete. Then, we can calculate the number of moles of cobalt(III) oxide produced.
Calculate the molar mass of cobalt(III) oxide (Co2O3).
Cobalt (Co) has a molar mass of approximately 58.933 grams per mole.
Oxygen (O) has a molar mass of approximately 16.00 grams per mole.
Cobalt(III) oxide (Co2O3) consists of two cobalt atoms and three oxygen atoms.
Molar mass of Co2O3 = (2 * molar mass of Co) + (3 * molar mass of O)
= (2 * 58.933 g/mol) + (3 * 16.00 g/mol)
= 117.866 g/mol + 48.00 g/mol
≈ 165.866 g/mol
Calculate the theoretical yield of cobalt(III) oxide when 41% of the reaction is complete.
41% of 10.49 grams = 0.41 * 10.49 grams
≈ 4.299 grams
Convert the mass of cobalt(III) oxide to moles using its molar mass.
Moles of Co2O3 = mass / molar mass
= 4.299 g / 165.866 g/mol
≈ 0.0259 moles
Therefore, approximately 0.0259 moles of cobalt(III) oxide will be produced when the reaction is 41% complete. Rounded to three significant figures, the answer is 0.0259 moles.
Explanation:
