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A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 10 minutes. Air traffic control approved a new flight plan that will allow her to arrive three times faster than she calculated in her original flight plan. Let x represent the time, in minutes, of her original flight. Create an equation that can be used to predict the number of minutes after 4:00 pm she will arrive at her destination. (1 point)

y equals one third times x plus 10

y = 3x + 10

y equals one third times x minus 10

y = 3x − 10

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Answer:

y = (1/3)x + 10

Step-by-step explanation:

Let's break down the situation:

The pilot's original departure time was 4:00 pm.

Due to air traffic, her departure has been delayed by 10 minutes. So, the time of her departure is 4:00 pm + 10 minutes = 4:10 pm.

The new flight plan approved by air traffic control allows her to arrive three times faster than her original flight plan.

Let x represent the time, in minutes, of her original flight. Since she will arrive three times faster, the time it will take for her to arrive at her destination will be x divided by 3.

So, if she departs at 4:10 pm, the time it takes to arrive at her destination (let's call this y) will be:

y = x / 3

However, we need to consider that x represents the time of her original flight, not her actual departure time. Since her original departure time was at 4:00 pm, x will also represent the time elapsed from 4:00 pm until her arrival.

So, the equation for predicting the number of minutes after 4:00 pm she will arrive at her destination is:

y = x / 3 + 10

This equation represents the time taken for her flight divided by 3 (to represent arriving three times faster) plus the 10-minute delay. Therefore, the correct equation is:

y equals one third times x plus 10

y = (1/3)x + 10

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