Question

If a 2.0 kg ball is dropped and lands on a spring with a constant of K = 5000, compressing it 10 cm. What height from the uncompressed spring was the ball dropped. ?

Answer 1

Answer:

1.18 m

Explanation:

Energy is conserved.

Potential energy = elastic energy

PE = EE

mg (h+x) = ½ kx²

(2.0 kg) (9.8 m/s²) (h + 0.10 m) = ½ (5000 N/m) (0.10 m)²

h = 1.18 m