Question

Consider the triangle below.
16
b
45°
C
Find the exact value of b and C

Answer 1

Answer:

• $\sf b=16cm \:\:and \:\:c= 16\sqrt{2}$

Step-by-step explanation:

In the figure 'b' and 'c' represents perpendicular and hypotenuse respectively.
So, in order to tackle this question we will use the concept of trigonometry.

$\sf tan 45^{0} = \frac{perpendicular}{base} \\\\\sf tan 45^{0} = 1= \frac{b}{16}\\\\b=16$

Now as we have found the value of perpendicular we can either use pythagoras or the concept of trigonometry.

Here I will use Pythagoras theorem.

$\sf \implies b^{2} + 16^2 = c^2\\\implies 16^2+16^2=c^2\\\implies c= 16\sqrt{2}$