A particle moves along the x-axis (units in cm). Its initial position at t=0 sec is f(0) = 13. The figure shows the graph of the particle's velocity f'(t). Thenumbers are the areas of the enclosed regions.

The position of other particle at t = c, is given by f(c). What is the position of the particle at time t = c?

A particle moves along the xaxis units in cm Its initial position at t0 sec is f0 13 The figure shows the graph of the particles velocity ft Thenumbers are the class=

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Answer:

  f(c) = -54 cm

Step-by-step explanation:

You want the position of a particle at t=c, given f(0) = 13 cm and the velocity f'(t) graph is shown.

Area

The area under the velocity curve has units of (cm/s)×(s) = cm. When the area is below the time axis, the change in position is negative.

The position at t = c will be the sum of the initial position and the changes indicated by the velocity curve.

  (position at t=c) = (13 cm) -(11 cm) +(14 cm) -(70 cm) = -54 cm

The position of the particle at t = c is f(c) = -54 cm.

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