Answer:
The average rate of change from x=0 to x=1 for f(x) is 0.
Step-by-step explanation:
We are given the function [tex]f(x)=-3x^{4}-x^{3}+3x^{2}+x+3[/tex].
Now, the rate average rate of change of a function from [tex]y=x_{1}[/tex] to [tex]y=x_{2}[/tex] is given by [tex]\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}[/tex].
As, we need the rate of change from x = 0 to x = 1.
So, we will find the values of f(0) and f(1).
i.e. [tex]f(0)=-3\times0^{4}-0^{3}+3\times0^{2}+0+3[/tex] i.e. f(0) = 3
and [tex]f(1)=-3\times1^{4}-1^{3}+3\times1^{2}+1+3[/tex] i.e. [tex]f(1)=-3-1+3+1+3[/tex] i.e. f(1) = 3
Thus, the rate of change from x=0 to x=1 is [tex]\frac{f(1)-f(0)}{1-0}[/tex] i.e. [tex]\frac{3-3}{1-0}[/tex] i.e. 0
Hence, the average rate of change from x=0 to x=1 for f(x) is 0.