1) No; you are incorrect. "0" is NOT a solution.
Plug in "0" for "x" ;
8*0² + 23 =? 823? ;
8*0 + 23 =? 823? ;
0 + 23 = ? 823 ? ; No! ; "0 + 23 = 23 " ; NOT "823" .
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2) The answers: x = 10, -10 ; or, write as: x = ± 10 .
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To solve:
GIven: 8x² + 23 = 823 ;
Subtract "23" from EACH SIDE of the equation:
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8x² + 23 - 23 = 823 - 23 ;
to get:
8x² = 800 ;
Now, divide EACH SIDE of the equation by "8" ;
8x² / 8 = 800 / 8 ;
to get: x² = 100 ;
Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
√(x²) = √(100) ;
x = ± 10 .
The answers: x = 10, -10 ; or, write as: x = ± 10 .
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