Respuesta :
[tex]t=\frac{1}{2}(d+h)\quad|\cdot2\\\\2t=d+h\quad|(-d)\\\\\boxed{2t-d=h}[/tex]
Answer d)
Answer d)
We want to rewrite one function such that the dependent and independent variables are interchanged.
We will get that the function for h is:
[tex]h = 2t - d[/tex]
Here the initial function is:
[tex]t = (1/2)*(d + h)[/tex]
We need to solve it for h, this means isolating h in one side of the function, so let's do that:
[tex]t = (1/2)*(d + h)\\2t = d + h\\2t - d = h\\\\h = 2t - d[/tex]
So the function for h is the one you can see above: h = 2t - d.
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