Note that
1 km = 0.62 mi
Therefore
0.62 mi = 10³ m
1 mi = 1.6129 x 10³ m
Also,
1 h = 3600 s
The given speed is
[tex](14,000 \, \frac{mi}{h} )*( \frac{1.6129 \times 10^{3} \, m}{mi} )*( \frac{h}{3600 \, s} ) = 6.27 \times 10^{3} \, \frac{m}{s} \approx 6.3 \times 10^{3} \, \frac{m}{s} [/tex]
Answer: A. 6.3 x 10³ m/s