Respuesta :

solutions: x=3 , y=5 , z=2
x+y+z=10
2x-5y+2z=-15
4x+y-z=15
neato

hrm
write random numbers and find the result later
make sure you don't write 2 euations that are the same like x+y+z=1 and 2x+2y+2z=2


3x+2y-4z=?
5x-6y+3z=?
x+3y-5z=?

if we evaluate for x=3, y=5 and z=2

3x+2y-4z=11
5x-6y+3z=-9
x+3y-5z=8

there, a system of 3 euations with solution of (3,5,2)
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