Use your calculator and a table of values to find the exact value of limit as x goes to infinity of the product of x and the sine of 1 over x. (The limit as x approaches infinity)

Answer:
The exact value is 1.
Step-by-step explanation:
Here, given expression,
[tex]x\sin(\frac{1}{x})[/tex]
When we put, x = 5, 10, 15, 20, 25, 30, 35, 40, 45, 55,.....
In the expression,
We found that the value of the expression is approaches to 1,
Hence, the exact value of,
[tex]\lim_{x\rightarrow \infty} x\sin(\frac{1}{x})[/tex] is 1.
Alternative method :
[tex]\lim_{x\rightarrow \infty} x\sin(\frac{1}{x})[/tex]
[tex]=\lim_{x\rightarrow \infty} \frac{\sin(\frac{1}{x})}{\frac{1}{x}}[/tex]
By L'hospital's rule,
[tex]=\lim_{x\rightarrow \infty}\frac{\frac{-\cos(\frac{1}{x})}{x^2}}{-\frac{1}{x^2}}[/tex]
[tex]=\lim_{x\rightarrow \infty} \frac{\cos(\frac{1}{x})}{1}[/tex]
[tex]=\lim_{x\rightarrow \infty} \cos(\frac{1}{x})[/tex]
[tex]=\cos(\frac{1}{\infty})[/tex]
[tex]=\cos(0)[/tex]
[tex]=1[/tex]