The distance the car would travel depends on the gas mileage rating. For example. if the car is a Honda insight with a gas mileage rating of 57 mi/gal, then it would be able to travel 8.60 km with 355 mL of gasoline.
FURTHER EXPLANATION
To solve this problem, the following steps must be done:
For this problem, the following conversion factors will be used:
(gas mileage rating) 57 mi = 1 gal
1 gal = 3.785 L
1 mi = 1.6093 km
STEP 1: Assuming that the car is a Honda Insight, then the gas mileage rating is 57 mi/gal.
STEP 2: Since the gas mileage rating is given per gallon of gasoline, the volume of gasoline given (355 mL) must be converted to gallons.
[tex]volume \ of \ gasoline \ = 355 \ mL \times \frac{1 \ L}{1000 \ mL} \times \frac{1 \ gal}{3.785 \ L}\\\\boxed {volume \ of \ gasoline \ = 0.09379 \ gal}[/tex]
STEP 3. Determine the distance covered in 0.09379 gallons of gasoline.
[tex]distance \ traveled \ = 0.09379 \ gal \times \frac{57 \ mi}{1 \ gal} \times \frac{1.6093 \ km}{1 \ mi}\\\boxed {distance \ traveled \ = 8.603 \ km}\\\\[/tex]
Since the given problem has 2 significant figures (based on the gas mileage rating), the final answer must also be expressed with 2 significant figures. Therefore,
[tex]\boxed {\boxed {distance \ traveled \ = 8.6 \ km}}[/tex]
Keywords: conversion, SI units
