Respuesta :
Answer:
[tex]\frac{1}{9}[/tex]
Step-by-step explanation:
Given :A spinner has three equal sections labeled 1, 2, and 3. It is spun twice.
Solution :Which expression can be used to determine P(2, then 1)?
Solution :
Total no. of events = {1,2,3}=3
When it is spin for the first time .
Since we are given in the first spin she should get 2
No. of Favorable events ={2}=1
probability of getting 2 = [tex]\frac{\text{No. of favorable events}}{\text{No. of total events}}[/tex]
= 1/3
In second spin she should get 1
No. of Favorable events ={1}=1
probability of getting 1= [tex]\frac{\text{No. of favorable events}}{\text{No. of total events}}[/tex]
=[tex]\frac{1}{3}[/tex]
Thus P(2, then 1) = [tex]\frac{1}{3} *\frac{1}{3}[/tex]
Hence the expression : P(2, then 1) = [tex]\frac{1}{3} *\frac{1}{3}[/tex]
= [tex]\frac{1}{9}[/tex]
