Question

help here.... this is question is on factorization of quadratic equations

Answer 1

forgive me if I've read your question wrong but I see
$\frac{20-45x^2}{6x^2-x-2}$
$= \frac{5(4-9x^2)}{6x^2-x-2} = \frac{5(2-3x)(2+3x)}{6x^2-x-2}$
$= \frac{5(2-3x)(2+3x)}{(3x+2)(3x-1)} = \frac{5(2-3x)}{3x-1}$