Question

Find the equation of a line with slope -3 and goes through the point (-5,2)

Answer 1

y - y₁ = m(x - x₁)
y - 2 = -3(x - (-5))
y - 2 = -3(x + 5)
y - 2 = -3(x) - 3(5)
y - 2 = -3x - 15
  + 2            + 2
     y = -3x - 13