You have to [tex]subtract [/tex] by [tex] \frac{1}{3}a [/tex] on [tex]EACH[/tex] of the [tex]sides [/tex] you're [tex]working [/tex] with!
[tex] \frac{4}{5}a + 3 - \frac{1}{3}a - 8 - \frac{1}{3}a [/tex]
Which [tex]gives [/tex] us: [tex] \frac{7}{15}a + 3 = -8 [/tex]
[tex]Now, [/tex] that we got these [tex]steps[/tex] out of the way, let's [tex]subtract [/tex] [tex]3[/tex] from the sides you're working with!
[tex] \frac{7}{15}a + 3 - 3 \\ = -8 -3 [/tex]
[tex] \frac{7}{15}(a) = -11[/tex]
We have gotten these [tex]steps [/tex] out of the way now lets [tex]multiply [/tex] by [tex] \frac{15}{7} [/tex] on your [tex]sides[/tex] because, it is the [tex]reciprocal [/tex] of [tex] \frac{7}{15} [/tex]
So, [tex] \frac{15}{7}( \frac{7}{15}a ) = \frac{15}{7} (-11)[/tex]
Cancel out: [tex] \frac{15}{7}( \frac{7}{15} )[/tex] because, it equals to:[tex]1[/tex]
[tex] \frac{15}{7}(-11) = \frac{-165}{7} [/tex]
Therefore, your [tex]answer [/tex] is: [tex] \frac{-165}{7} [/tex] [tex]aka[/tex] [tex] 23\frac{4}{7} [/tex]
Good luck on your assignment and enjoy your day
~[tex]MeIsKaitlyn:)[/tex]
