Respuesta :
We can use the plack equation for this, E = hv, where E is energy, h is the plack constant (6.626*10⁻³⁴ J*s) and v is the frequency. We were given a wavelength, which we'll call λ, where we can use v = c/λ (c is the speed of light = 3*10⁸ m/s) to plug into the plack equation. Doing so, we get E = hc/λ, where we can plug in numbers (remember 1 nm = 10⁻⁹ m) so E = (6.626*10⁻³⁴ J*s)*(3*10⁸ m/s)/(535 *10⁻⁹ m) = 3.72 *10⁻¹⁹ J and that's the energy of our photon emission
The energy of the photon emitted is about 3,72 × 10⁻¹⁹ Joule
Further explanation
The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem !
Given:
λ = 535 nm = 5.35 × 10⁻⁷ m
h = 6.63 × 10⁻³⁴ Js
c = 3 × 10⁸ m/s
Unknown:
E = ?
Solution:
[tex]E = h \times \frac{c}{\lambda}[/tex]
[tex]E = 6.63 \times 10^{-34} \times \frac{3 \times 10^8}{5.35 \times 10^{-7}}[/tex]
[tex]E \approx 3.72 \times 10^{-19}[/tex]
Learn more
- Photoelectric Effect : https://brainly.com/question/1408276
- Statements about the Photoelectric Effect : https://brainly.com/question/9260704
- Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544
Answer details
Grade: College
Subject: Physics
Chapter: Quantum Physics
Keywords: Quantum , Physics , Photoelectric , Effect , Threshold , Wavelength , Stopping , Potential , Copper , Surface , Ultraviolet , Light
