a square has 4 sides of equa length
the perimiter is 4 times the side, or P=4s where s=length of 1 side
the area is length times witdth, but since the length=width, area=s² where s is the length of one side
so express A=s² in terms of P when P=4s
solve for s first in P=4s
P=4s
divide both sides by 4
[tex]\frac{P}{4}=s[/tex]
subsitute [tex]\frac{P}{4}[/tex] for s in the other eqaution
[tex]A=s^2[/tex]
[tex]A=(\frac{P}{4})^2[/tex]
[tex]A=\frac{P^2}{16}[/tex]
in terms of the perimiter, the area is [tex]A=\frac{P^2}{16}[/tex]