Question

shift y= 5√x +3 horizontally 2 units to the right and stretched by a factor of 3 (stretched vertically about the fixed y=3 line).

Answer 1

horizontal shift 2 uniits to the right gives

y = 5 sqrt(x - 2) + 3

Then a vertical stretch factor 3  gives


y = 3[5sqrt(x-2) + 3)

or  y = 15sqrt(x - 2) + 9

Answer 2

Answer:Explained

Step-by-step explanation:

Given

equation of line is $y=5\sqrt{x}+3$

First We need to shift 2 units horizontally

Thus $y=5\sqrt{x-3}+3$

Now Stretched by a factor of 3 about the fixed y=3

that is the y is 3 times of previous value

$y=3\left ( 5\sqrt{x-3}+3\right )$