First calculate for the volume of the cylindrical cumulus cloud:
V = π r^2 h
V = π (1.0 km)^2 * 3.2 km
V = 3.2π km^3 = 10.05 km^3
We know that there are 60 water drops per cm^3. Therefore:
drops = 10.05 km^3 * (60 drop / cm^3) * (100,000 cm /
km)^3
drops = 6.032 x 10^17 drops
Calculating for the volume of 1 drop:
Vdrop = (4π/3) r^3
Vdrop = (4π/3) * (10 x 10^-6 m)^3
Vdrop = 4.19 x 10^-15 m^3
Hence total volume of the drop is:
Vtotal drops = 6.032 x 10^17 drops * 4.19 x 10^-15 m^3 /
drop
Vtotal drops = 2,526.68 m^3
