Question

Which exponential function has an initial value of 2?
O f(x)=2(3x)
O f(x)=3(2)
x
-2
f(x)
118
1

Answer 1

Answer:

The correct answer is Option (A) f(x)=2(3^x).

Step-by-step explanation:

Given , the initial value of the exponential fun is 2.

Then,

f(x) = 2(3^x)

For x = 0 ,

f(x) = 2(3^0)

f(x) = 2(1)      (because 3^0 =1)

f(x) = 2

Therefore, the initial value of the fun f(x) = 2