Question

A parabola drawn on a coordinate plane has vertex (1,−2) and focus (4,−2) . The parabola opens to the right. Which of the following is an equation of this parabola

Answer 1

Answer: (y+2)^2 =12(x-1)

Step-by-step explanation:

Step 1 Find the distance from the vertex to the focus. \(p=4-1=3\)

Step 2 Use the vertex and focus to find the equation of the parabola. \((y-(-2))^{2}=4\cdot 3(x-1)\) \((y+2)^{2}=12(x-1)\)

Solution The equation of the parabola is \((y+2)^{2}=12(x-1)\).