Question

5 in
Find the area.
Area of A =
[ ? ] in²
Area of □ =
in²
9 in
16 in
Remember:
A₁ = bh
Area of Figure =
=
in²

Answer 1

Answer :

• a(∆) = 40 in^2
• a(r) = 144 in^2
• a(f) = 184 in^2

Explanation :

area of a triangle is given by,

• a(∆) = 1/2bh
• a(∆) = 1/2*16in*5in
• a(∆) = 40 in^2

area of a rectangle is given by,

• a(r) = bh
• a(r) = 9in*16in
• a(r) = 144 in^2

thus,

the area of the figure would be,

• a(f) = a(∆) + a(r)
• a(f) = 40 in^2 + 144 in^2
• a(f) = 184 in^2

___

tripped,tysm msm<3

Answer 2

Answer:

$A_\triangle = 40 \, \textsf{in}^2$

  $A \boxed{\quad } = 144 \, \textsf{in}^2$

$A_{\textsf{total}} = 184 \, \textsf{in}^2$

Step-by-step explanation:

To find the total area of the figure, which consists of a triangle and a rectangle, we add the individual areas of each shape.

Area of Triangle ($A_\triangle$):

  The area of a triangle is given by the formula:

$A_\triangle = \dfrac{1}{2} \times \textsf{base} \times \textsf{height}$.

    Given:

• Base = 16 in,
• Height = 5 in.

Substitute the value and calculate:

  $A_\triangle = \dfrac{1}{2} \times 16 \times 5$

$A_\triangle = 40 \, \textsf{in}^2$

Area of Rectangle ($A\boxed{}$):

  The area of a rectangle is given by the formula:

$A\boxed{\quad} = \textsf{length} \times \textsf{width}$. 

  Given:

• Length = 16 in,
• Width = 9 in.

Substitute the value and calculate:  

  $A\boxed{\quad } = 16 \times 9$

  $A\boxed{\quad } = 144 \, \textsf{in}^2$

Total Area of the Figure ($A_{\textsf{total}})$:

  To find the total area, add the individual areas of the triangle and the rectangle.  

  $A_{\textsf{total}} = A_\triangle + A\boxed{\quad}$

$A_{\textsf{total}} = 40 + 144$

$A_{\textsf{total}} = 184 \, \textsf{in}^2$

Therefore, the total area of the figure is $184 \, \textsf{in}^2$.