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Rt c if you were to hit a ping pong ball of mass 0.0029 g with the same force that caused a 0.058-g tennis ball to move with an acceleration of 10 m/s2 , what would the acceleration a of the ping pong ball be? express your answer in meters per second squared.

Respuesta :

F=ma
You know the acceleration and mass of the tennis ball, now you can find the force applied by substituting it into the formula. Also I am assuming you meant to write your units in kg because that seems very light for grams. I am sorry if I misunderstood. 
F=ma
  = (0.058kg)(10m/s²)
  = 0.58N
Now that you know how much force was exerted you can solve for how much acceleration the ping pong ball will have.
F=ma
a=F/m
  =(0.58N)/(0.029kg)
  =20m/s²
Hope this helps!

The acceleration of the ping pong ball would be 200 m/s²

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Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\boxed {\Sigma F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

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Given:

mass of ping pong ball = m₁ = 0.0029 g

mass of tennis ball = m₂ = 0.058 g

acceleration of tennis ball = a₂ = 10 m/s²

Asked:

acceleration of ping pong ball = a₁ = ?

Solution:

[tex]\Sigma F_{\texttt{ping pong ball}} = \Sigma F_{\texttt{tennis ball}}[/tex]

[tex]m_1 a_1 = m_2 a_2[/tex]

[tex]0.0029 \times a_1 = 0.058 \times 10[/tex]

[tex]0.0029 \times a_1 = 0.58[/tex]

[tex]a_1 = 0.58 \div 0.0029[/tex]

[tex]a_1 = 200 \texttt{ m/s}^2[/tex]

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Conclusion :

The acceleration of the ping pong ball would be 200 m/s²

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Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

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